(5x^2+15x+8)/20x=0

Solution for (5x^2+15x+8)/20x=0 equation:

(5x^2+15x+8)/20x=0


Domain of the equation: 20x!=0

x!=0/20

x!=0

x∈R


We multiply all the terms by the denominator


(5x^2+15x+8)=0

We get rid of parentheses

5x^2+15x+8=0

a = 5; b = 15; c = +8;
Δ = b2-4ac
Δ = 152-4·5·8
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{65}}{2*5}=\frac{-15-\sqrt{65}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{65}}{2*5}=\frac{-15+\sqrt{65}}{10}
$